3.(x-5)-2.(x-1) = 3
=> 3x-(-15) - 2x -2 = 3
=> 3x-2x = 3+2+15
=> x = 20
<=> 3x-15-2x-2=3
<=> 3x-2x = 3+15+2
<=> x = 20
\(3\left(x-5\right)-2\left(x-1\right)=3\)
\(\Rightarrow3x-15-2x+2=3\)
\(\Rightarrow x=3+15-2\)
\(\Rightarrow x=16\)
Vậy x = 16
\(3\left(x-5\right)-2\left(x-1\right)=3\)
\(\Leftrightarrow3x-15-2x+2=3\)
\(\Leftrightarrow x-13=3\)
\(\Leftrightarrow x=16\)
Vậy phương trình có nghiệm x = 16 .