Lời giải:
\((2x+3)^2+2x=-3\)
\((2x+3)^2+(2x+3)=0\)
\((2x+3)[(2x+3)+1]=0\)
\((2x+3)(2x+4)=0\)
\(\Rightarrow \left[\begin{matrix} 2x+3=0\\ 2x+4=0\end{matrix}\right.\Rightarrow \left[\begin{matrix} x=\frac{-3}{2}\\ x=-2\end{matrix}\right.\)
(2x+3)2+2x=−3(2x+3)2+2x=−3
(2x+3)2+(2x+3)=0(2x+3)2+(2x+3)=0
(2x+3)[(2x+3)+1]=0(2x+3)[(2x+3)+1]=0
(2x+3)(2x+4)=0(2x+3)(2x+4)=0
⇒[2x+3=02x+4=0⇒[x=−32x=−2
k bt đúng hay k nhưng chúc thành công -.-