phương trình này nhìn từ đầu cũng bik vô nghiệm ko có x
\(\frac{x+1}{99}+\frac{x+2}{99}=\frac{x+10}{99}+\frac{x+20}{99}\)
Nhân 2 vế cho 99 ta được:
\(99.\left(\frac{x+1}{99}+\frac{x+2}{99}\right)=99.\left(\frac{x+10}{99}+\frac{x+20}{99}\right)\)
=>x+1+x+2=x+10+x+20
=>2x+3=2x+30
=>0x=27 (vô lí)
Vậy ko tìm dc x
\(\frac{x+1}{99}+\frac{x+2}{99}=\frac{x+10}{99}+\frac{x+20}{99}\)
\(\frac{x+1}{99}+\frac{x+2}{99}=\frac{x+10}{90}+\frac{x+20}{80}\)
Tìm x :
\(\frac{1}{x}\)+\(\frac{2}{x}\)+\(\frac{3}{x}\)+....+\(\frac{99}{x}\)+\(\frac{100}{x}\)=5050
ai nhanh mình tik
Tìm x : \(\frac{x-2}{99}+\frac{x-3}{98}=\frac{x-4}{97}+\frac{x-5}{96}\)
Tính:
\(\left(\frac{99^9}{11^9}-\frac{99^{99}}{11^{99}}-\frac{99^{999}}{11^{999}}\right).\left(\frac{1}{5}-\frac{1}{7}-\frac{2}{35}\right)\)
Tính :
a) \(1\frac{1}{3}\) x \(1\frac{1}{8}\) x \(1\frac{1}{15}\) x \(1\frac{1}{24}\) x ................x \(1\frac{1}{99}\)
b) \(\frac{99}{98}\) - \(\frac{98}{97}\) + \(\frac{1}{97\cdot98}\)
Chứng minh :
a) \(\frac{1}{3}-\frac{2}{3^2}+\frac{3}{3^3}-\frac{4}{3^4}+...+\frac{99}{3^{99}}-\frac{100}{3^{100}}< \frac{3}{16}\) \(\frac{1}{3}-\frac{2}{3^2}+\frac{3}{3^3}+\frac{4}{4^4}+...+\frac{99}{3^{99}}-\frac{100}{3^{100}}< \frac{3}{16}\)
b)\(\frac{1}{41}+\frac{1}{42}+\frac{1}{43}+...+\frac{1}{79}+\frac{1}{80}< \frac{7}{12}\)
c) Cho \(S=\frac{3}{10}+\frac{3}{11}+\frac{3}{12}+\frac{3}{13}+\frac{3}{14}\)
Chứng minh \(1< S< 2\)
1. Tính hợp lý :
A = \(\frac{\left(1+2+3+...+100\right)x\left(101x102-101x101-50-51\right)}{2+4+8+16...+2048}\)
B = \(\frac{101+100+99+...+3+2+1}{101-100+99-98+...+3-2+1}\)
2. Tìm số tự nhiên x, biết :
a, 697 : \(\frac{15x+364}{x}\)=17
b, 92.4 - 27 = \(\frac{x+350}{x}\)+315
c, 720 : [ 41 - ( 2x -5)] = 40
d, (x+1) + (x+2) +...+ (x+100) = 5750
Tính D biết : \(D=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}}{\frac{99}{1}+\frac{98}{2}+\frac{97}{3}+...+\frac{1}{99}}\)