\(a,PTHH:4Al+3O_2\rightarrow\left(t^o\right)2Al_2O_3\\ b,n_{Al_2O_3}=\dfrac{30,6}{102}=0,3\left(mol\right)\\ n_{Al}=\dfrac{4}{2}.n_{Al_2O_3}=2.0,3=0,6\left(mol\right)\\ \Rightarrow m_{Al}=0,6.27=16,2\left(g\right)\\ c,n_{O_2}=\dfrac{3}{2}.n_{Al_2O_3}=\dfrac{3}{2}.0,3=0,45\left(mol\right)\\ \Rightarrow V_{O_2\left(đkc\right)}=0,45.24,79=11,1555\left(l\right)\)
a, \(4Al+3O_2\underrightarrow{t^o}2Al_2O_3\)
b, \(nAl_2O_3=\dfrac{30,6}{102}=0,3\left(mol\right)\)
\(nAl=\dfrac{4}{2}.0,3=0,6\left(mol\right)\)
\(mAl=0,6.27=16,2\left(g\right)\)
c, \(nO_2=\dfrac{3}{2}.0,3=0,45\left(mol\right)\)
\(VO_{2\left(đkc\right)}=0,45.24,79=11,1555\left(l\right)\)
a) PTHH: \(4Al+3O_2\rightarrow^{t^0}2Al_2O_3\).
b) \(n_{Al_2O_3}=\dfrac{m}{M}=\dfrac{30,6}{102}=0,3\left(mol\right)\)
-Theo PTHH trên, ta có:
\(n_{Al}=\dfrac{n_{Al_2O_3}}{2}.4=\dfrac{0,3}{2}.4=0,6\left(mol\right)\)
\(\Rightarrow m_{Al}=0,6.27=16,2\left(mol\right)\)
c) -Theo PTHH trên, ta có:
\(n_{O_2}=\dfrac{n_{Al_2O_3}}{2}.3=\dfrac{0,3}{2}.3=0,45\left(mol\right)\).
\(\Rightarrow V_{O_2\left(đktc\right)}=n.24,79=0,45.24,79=11,1555\left(l\right)\)
