Question

\(\dfrac{y-4}{4}\) +\(\dfrac{y+7}{8}\)=7

Answer 1

\(\dfrac{y-4}{4}+\dfrac{y+7}{8}=7\)

=>\(\dfrac{2y-8+y+7}{8}=7\)

=>3y-1=56

=>3y=57

=>\(y=\dfrac{57}{3}=19\)