\(\dfrac{x}{-2}=-\dfrac{8}{x}\)
\(\Rightarrow x^2=16\Rightarrow x\pm4\)
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\(\dfrac{x}{-2}=\dfrac{-8}{x}\Rightarrow x\cdot x=\left(-2\right)\cdot\left(-8\right)\Rightarrow x^2=16\Rightarrow x=\pm4\)
- Ta có: \(\dfrac{x}{-2}\)= \(\dfrac{-8}{x}\)
<=> x * x = -2 * (-8)
<=> x2 = 16
<=> x = \(\sqrt{16}\)
<=> x = 4
- Vậy x = 4 khi \(\dfrac{x}{-2}\)= \(\dfrac{-8}{x}\).
\(\dfrac{x}{-2}=\dfrac{-8}{x}\Rightarrow x.x=\left(-2\right)\left(-8\right)\Rightarrow x^2=16\Rightarrow x=\pm4\)
\(\dfrac{x}{-2}=\dfrac{-8}{x}\)
\(\Rightarrow x^2=16\)
\(\Rightarrow x=\pm4\)