\(\dfrac{\left(2^3.5.7\right).\left(5^2.7^3\right)}{2.5.\left(7^2\right)}=\dfrac{2^3.\left(5.5^2\right).\left(7.7^3\right)}{2.5.7^2}\)
\(=\dfrac{2^3.5^3.7^4}{2.5.7^2}=\left(2^3:2\right).\left(5^3:5\right).\left(7^4:7^2\right)=2^2.5^2.7^2\)
=\(\left(2.5.7\right)^2=4900\)
(23 . 5 . 7) . (52 . 73) / 2 . 5 (72)
= (8 . 5 . 7) . (25 . 343) / 2 . 5 . 49
= 280 . 8575 / 490
= 2401000 / 490
= 4900
=(8.5.7).(25.343)/10.49
=280.8575/490
=2401000/490
=490