Question

\(\dfrac{3}{7}+\dfrac{1}{7}:x=\dfrac{3}{14}\)

Answer 1

\(\dfrac{3}{7}+\dfrac{1}{7}:x=\dfrac{3}{14}\)

⇒ \(\dfrac{1}{7}:x=\dfrac{3}{14}-\dfrac{3}{7}\)

⇒ \(\dfrac{1}{7}:x=\dfrac{-3}{14}\)

⇒ x= \(\dfrac{1}{7}:\dfrac{3}{14}\)

⇒ x=\(\dfrac{-2}{3}\)

Answer 2

\(\dfrac{3}{7}+\dfrac{1}{7}:x=\dfrac{3}{14} <=> \dfrac{6x+2-3x}{14x}=0 (*) điều kiện x khác 0 pt(*)<=>6x+2-3x=0<=>3x=-2<=>x=\dfrac{-2}{3} Vậy x = \dfrac{-2}{3}\)