Question

\(\dfrac{3}{4}\) - \(\sqrt{\dfrac{3}{12}}+\dfrac{\left(\sqrt{3}\right)}{4}^{2^{ }}\)

Answer 1

=3- căn 6 / 2

Answer 2

\(\dfrac{3}{4}-\sqrt[]{\dfrac{3}{12}+\dfrac{\left(\sqrt[]{3^2}\right)}{4}}\)

\(=\dfrac{3}{4}-\sqrt[]{\dfrac{1}{4}+\dfrac{3}{4}}\)

\(=\dfrac{3}{4}-\dfrac{1}{2}+\dfrac{3}{4}\)

\(=1\)

Answer 3

\(\dfrac{3}{4}-\sqrt{\dfrac{1}{4}}+\dfrac{3}{4}=\dfrac{6}{4}-\dfrac{1}{2}=1\)