Violympic toán 7

PL

\(\dfrac{15}{11}\)+\(\dfrac{8}{13}\)-\(\dfrac{4}{11}\)+\(\dfrac{18}{13}\)

DH
9 tháng 12 2017 lúc 19:24

\(\dfrac{15}{11}+\dfrac{8}{13}-\dfrac{4}{11}+\dfrac{18}{13}\)

\(=\left(\dfrac{15}{11}-\dfrac{4}{11}\right)+\left(\dfrac{8}{13}+\dfrac{18}{13}\right)\)

\(=1+2\)

\(=3\)

Bình luận (0)
NC
20 tháng 12 2017 lúc 19:01

\(\dfrac{15}{11}+\dfrac{8}{13}-\dfrac{4}{11}+\dfrac{18}{13}=\left(\dfrac{15}{11}-\dfrac{4}{11}\right)+\left(\dfrac{8}{13}+\dfrac{18}{13}\right)=\dfrac{11}{11}+\dfrac{26}{13}=1+2=3\)

Bình luận (0)