Question

D=(11 nhân 3^22 nhân 3^7 trừ 9^15) chia 6^28 

Answer 1

\(\left(11\times3^{22}\times3^7-9^{15}\right)\div6^{28}=\left[11\times3^{29}-\left(3^2\right)^{15}\right]\div\left(2\times3\right)^{28}=\left(11\times3^{29}-3^{30}\right)\div\left(2^{28}\times3^{28}\right)\)

\(=\frac{3^{29}\times\left(11-3\right)}{2^{28}\times3^{28}}=\frac{3\times8}{2^{28}}=\frac{3\times2^3}{2^{28}}=\frac{3}{2^{25}}\)

 

Answer 2

:v ..... Viết đề LaTex đi chị :v ..... 

Answer 3

Đề có sai không

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