Question

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Answer 1

a)\(A=x^2y^3+xy\)

\(khix=1vày=\dfrac{1}{2}tacó:\)

\(A=1^2\left(\dfrac{1}{2}\right)^3+1\times\dfrac{1}{2}\)

\(A=\dfrac{1}{8}+\dfrac{1}{2}\)

\(A=\dfrac{5}{8}\)

b)\(B=4x^3+x-2022\)

\(khi\left|x\right|=2tacó:\)

\(B=4\times2^3+2-2022\)

\(B=4\times8+2-2022\)

\(B=32+2-2022\)

\(B=-1988\)