Question

Chứng minh rằng:

\(81^7-27^9-9^{13}⋮45\)

Answer 1

Ta có:\(81^7-27^9-9^{13}=\left(3^4\right)^7-\left(3^3\right)^9-\left(3^2\right)^{13}=3^{28}-3^{27}-3^{26}\)

\(\Rightarrow3^4.3^{24}-3^3.3^{24}-3^2-3^{24}=\left(3^4-3^3-3^2\right).3^{24}=\left(81-27-9\right).3^{24}=45.3^{24}⋮45\)

Vậy \(81^7-27^9-9^{13}⋮45\)