Question

Cho\(\frac{3x-y}{x+y}=\frac{3}{4}\)Tính \(\frac{x}{y}\)

Answer 1

\(\frac{3x-y}{x+y}=\frac{3}{4}\\ \Rightarrow3\left(x+y\right)=4\left(3x-y\right)\\ \Rightarrow3x+3y=12x-4y\\ \Rightarrow12x-3x=4y+3y\\ \Rightarrow9x=7y\\ \Rightarrow\frac{x}{y}=\frac{7}{9}\)

Answer 2

\(\frac{3x-y}{x+y}=\frac{3}{4}\)

\(\Rightarrow\left(3x-y\right).4=\left(x+y\right).3\)

\(\Rightarrow12x-4y=3x+3y\)

\(\Rightarrow12x-3x=3y+4y\)

\(\Rightarrow9x=7y\)

\(\Rightarrow\frac{x}{y}=\frac{7}{9}\)

Vậy \(\frac{x}{y}=\frac{7}{9}.\)

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