CMR C = \(\dfrac{1}{2}.\dfrac{3}{4}.\dfrac{5}{6}...\dfrac{9999}{10000}< \dfrac{1}{100}\)
bài 4 : cmr :
c) C = \(\dfrac{1}{2}.\dfrac{3}{4}.\dfrac{5}{6}....\dfrac{9999}{10000}< \dfrac{1}{100}\)
bài 5
cho A=\(\dfrac{1}{2}\cdot\dfrac{3}{4}\dfrac{5}{6}\cdot...\cdot\dfrac{9999}{10000}\)
So sánh a với \(\dfrac{1}{100}\)
Chứng minh rằng:
a=1+1/2^2+1/3^2+1/4^2+...+1/100^2<2
b=1+1/2+1/3+1/4+...+1/63<6
c=1/2.3/4.5/6....9999/10000<1/100
bài 17: Cho A = \(\frac{1}{2}.\frac{3}{4}.\frac{5}{6}..........\frac{9999}{10000}.\)Hãy so sánh A với 0,01
Chứng minh rằng:
a, A= 1+\(\dfrac{1}{2}\)+ \(\dfrac{1}{3}\)+\(\dfrac{1}{4}\)+......+\(\dfrac{1}{63}\)<6
b, B= \(\dfrac{1}{2}\).\(\dfrac{3}{4}\).\(\dfrac{5}{6}\)......\(\dfrac{9999}{10000}\)< \(\dfrac{1}{100}\)
Cho A=1/2.3/4.5/6......9999/10000
So sánh A với 0,01
Câu 1: Tìm x biết
a) \(-\dfrac{2}{3}\)\(\left(x-\dfrac{1}{4}\right)\) = \(\dfrac{1}{3}\left(2x-1\right)\) b) \(\dfrac{1}{5}.2^x+\dfrac{1}{3}.2^{x+1}=\dfrac{1}{5}.2^7+\dfrac{1}{3}.2^8\)
Câu 2: a) Cho A = \(\dfrac{1}{2}.\dfrac{3}{4}.\dfrac{5}{6}......\dfrac{9999}{10000}\)
So sánh A vs 0,01
b) Chứng tỏ rằng: \(\left[\left(1+2+3+....+n\right)-7\right]⋮̸10\)
Cho A = 1-2+3-4+5-6+....+99-100. Tong A co chia het cho 2 , 3 ,4 khong
