\(n_{SO_2}=\dfrac{44.8}{22.4}=2\left(mol\right)\)
\(n_{NaOH}=4\cdot2=8\left(mol\right)\)
\(\dfrac{n_{NaOH}}{n_{SO_2}}=\dfrac{8}{2}=4\)
\(\Rightarrow\text{Tạo ra muối }Na_2SO_3\)
\(2NaOH+SO_2\rightarrow Na_2SO_3+H_2O\)
\(............2...........2\)
\(m_{Na_2SO_3}=2\cdot126=252\left(g\right)\)