Question

câu 1 . tìm x

a. \(x:3\dfrac{1}{15}=1\dfrac{1}{2}\)

b.\(x.\dfrac{3}{2}=\dfrac{-7}{6}\)

c. \(\dfrac{5}{6}+\dfrac{1}{4}:x=\dfrac{-2}{3}\)

d. \(\dfrac{-2}{13}.x=\dfrac{-9}{26}\)

e. \(\dfrac{1}{2}.x-\dfrac{1}{10}=\dfrac{2}{3}\)

f.\(-52+\dfrac{2}{3}.x=-46\)

Answer 1

a. \(x:3\dfrac{1}{15}=1\dfrac{1}{2}\)

\(x:\dfrac{46}{15}=\dfrac{3}{2}\)

\(x=\dfrac{3}{2}.\dfrac{46}{15}=\dfrac{23}{5}\)

b. \(x.\dfrac{3}{2}=-\dfrac{7}{6}\)

\(x=-\dfrac{7}{6}:\dfrac{3}{2}=-\dfrac{7}{9}\)

c. \(\dfrac{5}{6}+\dfrac{1}{4}:x=-\dfrac{2}{3}\)

\(\dfrac{13}{12}:x=-\dfrac{2}{3}\)

\(x=\dfrac{13}{12}:\left(-\dfrac{2}{3}\right)=-\dfrac{13}{8}\)

Còn lại tương tự thôi

\(\)