bài 1:tìm x biết
a) x + 1/9 - 3/5= 3/6 b) 3/4 - x + 6/-11 = 5/6
bài 2: tìm x biết
a) x : 13/16= 5/-8 b) x . -14/28 = 6/-9 - 2/15
c) -12/25 . (3/4 -x + 6/-11 - 5/6) = 0 d) x: 4/28 = 13/-19 + 8/25
bài 3:tìm x biết
a) 62/7.x= 29/9:3/56 b) 1/5:x=1/5+1/7 c)1/2a2+1 : x=2
ai bik câu nào thì giúp mink câu đó nhé. mink đnag cần gấp
Bài 1:
a ) \(x+\frac{1}{9}-\frac{3}{5}=\frac{3}{6}\)
\(x+\frac{1}{9}=\frac{3}{6}+\frac{3}{5}\)
\(x+\frac{1}{9}=\frac{11}{10}\)
\(x=\frac{11}{10}-\frac{1}{9}=\frac{89}{90}\)
Vậy \(x=\frac{89}{90}\)
b) \(\frac{3}{4}-x+\frac{6}{11}=\frac{5}{6}\)
\(\frac{3}{4}-x=\frac{5}{6}-\frac{6}{11}\)
\(\frac{3}{4}-x=\frac{19}{66}\)
\(x=\frac{3}{4}-\frac{19}{66}=\frac{61}{132}\)
Vậy \(x=\frac{61}{132}\)
Bài 2 :
a) \(x:\frac{13}{16}=\frac{5}{-8}\)
\(x=\frac{5}{-8}.\frac{13}{16}=-\frac{65}{128}\)
Vậy \(x=-\frac{65}{128}\)
b) \(x.\frac{-14}{28}=\frac{6}{-9}-\frac{2}{15}\)
\(x.\frac{-14}{28}=-\frac{4}{5}\)
\(x=-\frac{4}{5}:\frac{-14}{28}=\frac{8}{5}\)
Vậy \(x=\frac{8}{5}\)
bài 3: đúng 100% k tin có thể thử lại cho chắc ok
a, \(\frac{62}{7}x=\frac{29}{9}:\frac{3}{56}\\ \Leftrightarrow\frac{62}{7}x=\frac{1624}{27}\\ \Rightarrow x=\frac{1624}{27}:\frac{62}{7}=\frac{5684}{837}\)
b, \(\frac{1}{5}:x=\frac{1}{5}+\frac{1}{7}\\ \Leftrightarrow\frac{1}{5}:x=\frac{12}{35}\\ \Rightarrow x=\frac{1}{5}:\frac{12}{35}=\frac{7}{12}\)
ý c ghi rõ đầu bài dùm k khó làm lắm =3
Bài 1:
a) \(x+\frac{1}{9}-\frac{3}{5}=\frac{3}{6}\)
\(x+\frac{1}{9}=\frac{3}{6}+\frac{3}{5}\)
\(x+\frac{1}{9}=1\frac{1}{10}\)
\(x=1\frac{1}{10}-\frac{1}{9}\)
\(x=\frac{89}{90}\)
Vậy \(x=\frac{89}{90}\)
b) \(\frac{3}{4}-x+\left(\frac{6}{-11}\right)=\frac{5}{6}\)
\(x+\left(-\frac{6}{11}\right)=\frac{3}{4}-\frac{5}{6}\)
\(x+\left(-\frac{6}{11}\right)=-\frac{1}{12}\)
\(x=\left(-\frac{1}{12}\right)-\left(-\frac{6}{11}\right)\)
\(x=\frac{61}{132}\)
Vậy \(x=\frac{61}{132}\)
Bài 2:
a) \(x:\frac{13}{16}=-\frac{5}{8}\)
\(x=\left(-\frac{5}{8}\right)\cdot\frac{13}{16}\)
\(x=-\frac{65}{128}\)
Vậy \(x=-\frac{65}{128}\)
b) \(x\cdot\left(-\frac{14}{28}\right)=\left(\frac{6}{-9}\right)-\frac{2}{15}\)
\(x\cdot\left(-\frac{14}{28}\right)=-\frac{4}{5}\)
\(x=\left(-\frac{4}{5}\right):\left(-\frac{14}{28}\right)\)
\(x=1\frac{3}{5}\)
Vậy \(x=1\frac{3}{5}\)
c) \(\left(-\frac{12}{25}\right)\cdot\left[\frac{3}{4}-x+\left(\frac{6}{-11}\right)-\frac{5}{6}\right]=0\)
\(\frac{3}{4}-x+\frac{6}{-11}-\frac{5}{6}=0\)
\(\frac{3}{4}-x+\frac{6}{-11}=\frac{5}{6}\)
\(\frac{3}{4}-x=1\frac{25}{66}\)
\(x=-\frac{83}{132}\)
Vậy \(x=-\frac{83}{132}\)
d) \(x:\frac{4}{28}=\frac{13}{-19}+\frac{8}{25}\)
\(x:\frac{4}{28}=-\frac{173}{475}\)
\(x=-\frac{173}{3325}\)
Vậy \(x=-\frac{173}{3325}\)
Bài 3:
a) \(\frac{62}{7}\cdot x=\frac{29}{9}:\frac{3}{56}\)
\(\frac{62}{7}\cdot x=60\frac{4}{27}\)
\(x=6\frac{662}{837}\)
Vậy \(x=6\frac{662}{837}\)
b) \(\frac{1}{5}:x=\frac{1}{5}+\frac{1}{7}\)
\(\frac{1}{5}:x=\frac{12}{35}\)
\(x=\frac{7}{12}\)
Vậy \(x=\frac{7}{12}\)
