Question

Bài 1: Tính

a, (4/1/9+3/1/4). 2/1/4+2/3/4

b, 9/23. 5/8+ 9/23. 3/8 - 9/23

c, 1+ (9/10 - 4/5) : 3/1/6

d, (-7+/13/) - (13- / -7/ -25) - (25 +/- 10/ -9)

Answer 1

Giúp trả lời mấy câu hỏi này đi mk đang cần rất gấp

Answer 2

a, \(\left(4\dfrac{1}{9}+3\dfrac{1}{4}\right).2\dfrac{1}{4}+2\dfrac{3}{4}\)

\(=\left(\dfrac{37}{9}+\dfrac{13}{4}\right).\dfrac{9}{4}+\dfrac{11}{4}\)

\(=\dfrac{265}{36}.\dfrac{9}{4}+\dfrac{11}{4}\)

\(=\dfrac{265}{16}+\dfrac{11}{4}\)

\(=\dfrac{309}{16}\)

b, \(\dfrac{9}{23}.\dfrac{5}{8}+\dfrac{9}{23}.\dfrac{3}{8}-\dfrac{9}{23}\)

\(=\dfrac{45}{184}+\dfrac{27}{184}-\dfrac{9}{23}\)

\(=\dfrac{9}{23}-\dfrac{9}{23}\)

\(=\dfrac{1}{1}\)

c, \(1+\left(\dfrac{9}{10}-\dfrac{4}{5}\right)\div3\dfrac{1}{6}\)

\(=1+\left(\dfrac{9}{10}-\dfrac{4}{5}\right)\div\dfrac{19}{6}\)

\(=1+\dfrac{1}{10}\div\dfrac{19}{6}\)

\(=1+\dfrac{3}{95}\)

\(=1\dfrac{3}{95}\)

d, ???