a) 2|x-3|+|2x+5|=11
2x-6+2x+5=11
2x+2x = 11-5+6
4x = 12
x= \(\dfrac{12}{4}\)
x= 3
vậy x =3
b) |x-3| +|5-x| +2|x-4|=2
x-3+5-x+2x-8=2
x-x+2x = 2+3-5+8
2x = 8
x = \(\dfrac{8}{2}\)
x=4
vậy x = 4
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