Question

bài 1:

a)\(\frac{11x-1}{4}=\frac{5}{2}\)

b)\(\left(3x-6\right).\left(\frac{x}{9}-\frac{1}{3}\right)=0\)

c)\(M=c.\frac{5}{7}+c.\frac{7}{14}-c.\frac{17}{14}vớic=\frac{2018}{2019}-\frac{2019}{2020}\)

d)\(N=\frac{-7}{13}+\left(2-\frac{19}{13}\right)+\frac{2020}{2018}:\frac{202}{2018}\)

CÁC BẠN GIẢI GIÚP MÌNH NHA☺

Answer 1

a)

⇒ \(\frac{11x-1}{4}=\frac{10}{4}\)

⇒ 11x - 1 = 10

11x = 10 + 1 = 11

x = 11 : 11 = 1

b)

\(\left[{}\begin{matrix}3x-6=0\\\frac{x}{9}-\frac{1}{3}=0\end{matrix}\right.\) ⇒ \(\left[{}\begin{matrix}3x=0+6\\\frac{x}{9}=0+\frac{1}{3}\end{matrix}\right.\)⇒ \(\left[{}\begin{matrix}3x=6\\\frac{x}{9}=\frac{1}{3}\end{matrix}\right.\)⇒ \(\left[{}\begin{matrix}x=6:3\\\frac{x}{9}=\frac{3}{9}\end{matrix}\right.\)⇒\(\left[{}\begin{matrix}x=2\\x=3\end{matrix}\right.\)

Vậy x = 2 hoặc x = 3

c)

\(M=c\left(\frac{5}{7}+\frac{7}{14}-\frac{17}{14}\right)\)

\(M=c\left(\frac{10}{14}+\frac{7}{14}-\frac{17}{14}\right)\)

\(M=\left(\frac{2018}{2019}-\frac{2019}{2020}\right).0\)

M = 0

d)

\(N=\frac{-7}{13}+2-\frac{19}{13}+\frac{2020}{2018}.\frac{2018}{202}\)

\(N=\left(\frac{-7}{13}-\frac{19}{13}\right)+2+10\)

N = \(-2+2+10\)

N = 10