Question

bài 1

A = 50%.1\(\frac{1}{3}.20.\frac{7}{35}.0,75\)

bài 2: tìm x biết

a, \(\frac{1}{3}x+13\frac{1}{4}=16\frac{1}{4}\)

b, \(\frac{1}{3}+\frac{2}{3}x=\frac{-1}{4}\)

Answer 1

bài 1

A= \(\frac{1}{2}.\frac{4}{3}.20.\frac{7}{35}.0,75=2\)

bài 2

a,\(\Leftrightarrow\frac{1}{3}x+\frac{53}{4}=\frac{65}{4}\)

\(\Leftrightarrow\frac{1}{3}x=3\)

\(\Leftrightarrow x=9\)

vậy....

b, \(\Leftrightarrow\frac{2}{3}x=\frac{-7}{12}\)

\(\Leftrightarrow x=-\frac{7}{8}\)

vậy.......