\(6x+1\dfrac{1}{3}=5\dfrac{1}{2}x+2\dfrac{2}{3}\\ < =>6x-5\dfrac{1}{2}x=2\dfrac{2}{3}-1\dfrac{1}{3}\\ < =>\dfrac{1}{2}x=1\dfrac{1}{3}\\ < =>\dfrac{1}{2}x=\dfrac{4}{3}\\ =>x=\dfrac{4}{3}:\dfrac{1}{2}=\dfrac{4}{3}.2=\dfrac{8}{3}\)
\(6x+1\dfrac{1}{3}=5\dfrac{1}{2}x+2\dfrac{2}{3}\\ < =>6x-5\dfrac{1}{2}x=2\dfrac{2}{3}-1\dfrac{1}{3}\\ < =>\dfrac{1}{2}x=1\dfrac{1}{3}\\ < =>\dfrac{1}{2}x=\dfrac{4}{3}\\ =>x=\dfrac{4}{3}:\dfrac{1}{2}=\dfrac{4}{3}.2=\dfrac{8}{3}\)
Bài 2:Tìm x biết:
a)\(\dfrac{1}{7}+x=\dfrac{-2}{3}\)
b)\(\dfrac{-2}{3}:x=\dfrac{-5}{6}\)
c)\(\left\{\dfrac{3}{5}-2x\right\}.\dfrac{5}{8}=1\)
d)\(\dfrac{3}{4}+\dfrac{2}{5}x=\dfrac{29}{60}\)
e)\(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
f)\(\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\)
g)\(\left|X+\dfrac{1}{3}\right|-4=\dfrac{-1}{2}\)
h)\(\left(\dfrac{1}{32}\right)^x.8^{2x}=512\)
i)\(5,3x+\left(-3,3\right)x+1,7=-4,9\)
a)(\(\dfrac{2}{9}\)(6x-\(\dfrac{3}{4}\))-3(\(\dfrac{1}{4}\)x-\(\dfrac{1}{5}\))=\(\dfrac{-8}{15}\)
b)\(\dfrac{3}{4}\)(x-\(\dfrac{8}{9}\))-5(x-\(\dfrac{11}{15}\))+\(\dfrac{1}{2}\)x=5\(\dfrac{1}{12}\)
c)\(\dfrac{2}{3}\)(-3x-\(\dfrac{6}{5}\))-\(\dfrac{5}{7}\)(\(\dfrac{49}{15}\)-14x)=-2\(\dfrac{1}{3}\)
d)(12\(\dfrac{7}{8}\)-10\(\dfrac{13}{8}\)):x-1\(\dfrac{7}{33}\):\(\dfrac{8}{11}\)=1\(\dfrac{2}{3}\)
tìm x
\(\dfrac{5}{3}x-2\dfrac{1}{3}=-\dfrac{4}{3}.1\dfrac{1}{8}-\dfrac{2}{3}\)
\(2\dfrac{1}{6}:x-\dfrac{-5}{8}=\dfrac{-7}{15}:4\dfrac{1}{5}-\dfrac{-6}{7}\)
\(\left(\dfrac{5}{6}x-0,3\right):2\dfrac{1}{3}=25\%\)
\(\dfrac{4}{7}-\dfrac{2}{3}x=1,5+\dfrac{4}{5}x\)
GIÚP MÌNH NHÉ
TÌM X
A,\(\dfrac{3}{7}x-2\dfrac{1}{3}=0,5\)
b,\(\dfrac{4}{7}-\dfrac{2}{3}:x=1\dfrac{1}{4}\)
C,\(\left(\dfrac{2}{3}x+2\dfrac{1}{4}\right):3\dfrac{1}{5}=0,75\)
D,\(\left|\dfrac{4}{5}-\dfrac{2}{3}x\right|:\dfrac{1}{4}-\dfrac{2}{3}=1\)
GIÚP MÌNH NHÉ
a,\(\dfrac{-4}{5}-\left(\dfrac{2}{3}x+1\dfrac{1}{4}\right)=\dfrac{2}{7}\)
b\(\dfrac{5}{6}+\left(\dfrac{3}{4}-\dfrac{1}{2}:x\right)=\dfrac{-2}{3}\)
c\(\left(\dfrac{4}{5}x-1\dfrac{1}{3}\right):\dfrac{3}{4}=0,7\)
d\(\dfrac{5}{6}-\dfrac{3}{4}x=1\dfrac{1}{3}+0,5x\)
giúp mình nhé mình đang cần gấp
\(\dfrac{2}{3}x-\dfrac{3}{2}\left(x-\dfrac{1}{2}\right)=\dfrac{5}{12}\)
Tìm x biết :
x : \((3\dfrac{1}{2}-5\dfrac{1}{6})=4\dfrac{1}{5}-6\dfrac{2}{3}.\)
a) \(\dfrac{2}{3}\)x - \(\dfrac{1}{2}\) = \(\dfrac{1}{10}\)
b) ( \(2\dfrac{4}{5}\)x - 50 ) : \(\dfrac{2}{3}\)= 51
c) \(\dfrac{2}{3}\)x - \(\dfrac{1}{2}\)x = \(\dfrac{5}{12}\)
d) \(\dfrac{17}{2}\)- | 2x - \(\dfrac{3}{4}\)| = \(-\dfrac{7}{4}\)
đ) ( x + \(\dfrac{1}{5}\))2 + \(\dfrac{17}{25}\)= \(\dfrac{26}{25}\)
tìm x
a,\(\dfrac{6}{7}-\dfrac{3}{4}x=-1\dfrac{1}{2}x-3\)
b\(\left(4x-1\right)^2=\left(4x-1\right)^4\)
c\(\left(\dfrac{4}{5}-\dfrac{3}{4}:x\right)^3=\dfrac{-1}{27}\)
d\(\left|\dfrac{4}{3}-\dfrac{1}{4}x\right|:2\dfrac{1}{3}=0,5\)
giúp mình nhé