Question

(3-7/3+1/4)÷(4-31/6+9/4)

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Answer 1

\((3-\dfrac{7}{3}+\dfrac{1}{4}\))\(\div\)\(\left(4-\dfrac{31}{6}+\dfrac{9}{4}\right)\)=

\(\left(\dfrac{36}{12}-\dfrac{28}{12}+\dfrac{3}{12}\right)\div\left(\dfrac{48}{12}-\dfrac{62}{12}+\dfrac{27}{12}\right)\)=

\(\dfrac{11}{12}\div\dfrac{13}{12}\)=\(\dfrac{11}{12}\times\dfrac{12}{13}=\dfrac{11}{13}\)