\(2x+7=2^3\\ 2x+7=8\\ 2x=8-7\\ 2x=1\\ x=1:2\\ x=\dfrac{1}{2}\\ Vậyx=\dfrac{1}{2}\)
\(2x+7=2^3\)
\(2x+7=8\)
\(2x=8-7\)
\(2x=1\)
\(x=1:2\)
Vậy \(x=\dfrac{1}{2}=0.5\)
2\(x\) + 7 = 2\(^3\)
\(\Rightarrow\) 2\(x\) + 7 = 8
2\(x\) = 8 - 7
2\(x\) = 1
\(x\) = 1 : 2
\(x\) = \(\dfrac{1}{2}\) = 0,5