\(2^{x+1}.5^y=20^x\)
=>\(2^{x+1}.5^y=\left(2^2.5\right)^x\)
=>\(2^{x+1}.5^y=2^{2.x}.5^x\)
=>\(2^{x+1}=2^{2x}\) và \(5^y=5^x\)
=>\(x+1=2x\)
=>\(x=1\)
với \(5^y=5^x\)
=>\(x=y\)
=>\(y=1\)
Vậy \(x=1,y=1\)
Chúc Bạn học tốt
\(2^{x+1}.5^y=20^x\)
\(\Leftrightarrow2^{x+1}.5^y=\left(2^2.5\right)^x\)
\(\Leftrightarrow2^{x+1}.5^y=2^{2x}.5^x\)
\(\Leftrightarrow\left\{{}\begin{matrix}2^{x+1}=2^{2x}\\5^y=5^x\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x+1=2x\\y=x\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=1\\y=x\end{matrix}\right.\)
\(\Leftrightarrow x=y=1\)
Vậy ....