Question

(2x-3)^2=25

Answer 1

Ta có: \(\left(2x-3\right)^2=25\)

\(\Rightarrow\left(2x-3\right)^2=5^2\)

\(\Rightarrow2x-3=5\)

\(\Rightarrow2x=5+3=8\)

\(\Rightarrow x=\frac{8}{2}=4\)

Vậy: \(x=4\)

Answer 2

ta có:(2x-3)^2=5^(2

nen (2x-3)=5

2x=5+3

2x=8

x=8/2

x=4

Answer 3

Ta có: (2x-3)²=25

=> 2x-3 = \(\pm5\)

=>\(\left[{}\begin{matrix}2x-3=5\\2x-3=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-1\end{matrix}\right.\)

Vậy x\(\in\left\{4;-1\right\}\)