\(\left(2x^2-1\right)-5=44\)
\(2x^2-1=49\)
\(2x^2=50\)
\(x^2=25\)
\(x=\sqrt{25}=5\)
( 2x 2 - 1 ) - 5 = 44
\(\Rightarrow\) (2x2 - 1) = 44 + 5
\(\Rightarrow\) (2x2 - 1) = 49
\(\Rightarrow\) 2x2 = 49 + 1
\(\Rightarrow\) 2x2 = 50
\(\Rightarrow\) x2 = 25
\(\Rightarrow\) x2 = 52
\(\Rightarrow\) x = 5
(\(2x^2\)-1)=44+5
(\(2x^2\)-1)=49
\(2x^2\)=49+1
\(2x^2\)=50
\(x^2\)=50/2
\(x^2\)=25
\(x^2\)=5\(^2\)
Vậy x=5
(2x2-1)-5=44
\(\Rightarrow2x^2-1=44+5\)
\(\Rightarrow2x^2-1=49\)
\(\Rightarrow2x^2=49+1\)
\(\Rightarrow2x^2=50\)
\(\Rightarrow x^2=50:2\)
\(\Rightarrow x^2=25\)
\(\Rightarrow x^2=\sqrt{25}\)
\(\Rightarrow x=5\)
(2x2-1)-5=44
\(\Rightarrow\)2x2-1=44+5=49
\(\Rightarrow\)2x2=49+1=50
\(\Rightarrow\)x2=50:2=25
\(\Rightarrow\)\(x=\sqrt{25}=5\)
