\(2.\left(\dfrac{3}{4}-5x\right)=\dfrac{4}{5}-3x\)
= \(2.\dfrac{3}{4}-2.5x=\dfrac{4}{5}-3x\)
= \(\dfrac{3}{2}-10x=\dfrac{4}{5}-3x\)
= \(\dfrac{3}{2}-\dfrac{4}{5}=10x-3x\)
\(\dfrac{7}{10}\) = 7x
\(\dfrac{7}{10}:7=x\)
\(\dfrac{1}{10}=x\)
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