\(-\dfrac{2}{5}+\dfrac{4}{5}x=\dfrac{3}{5}\)
\(\dfrac{4}{5}x=\dfrac{3}{5}-\dfrac{-2}{5}\)
\(\dfrac{4}{5}x=\dfrac{3}{5}+\dfrac{2}{5}=1\)
\(\Rightarrow x=1:\dfrac{4}{5}=\dfrac{1.5}{4}=\dfrac{5}{4}\)
Vậy x = \(\dfrac{5}{4}\)
\(\dfrac{-2}{5}\)+\(\dfrac{4}{5}\).x=\(\dfrac{3}{5}\)
=>\(\dfrac{4}{5}\)x=\(\dfrac{4}{5}\)-\(\dfrac{-2}{5}\)
=>\(\dfrac{4}{5}\)x=\(\dfrac{6}{5}\)
=>x=\(\dfrac{6}{5}\):\(\dfrac{4}{5}\)
=> x=\(\dfrac{3}{2}\)
\(\dfrac{-2}{5}+\dfrac{4}{5}.x=\dfrac{3}{5}\)
\(\dfrac{4}{5}.x=\dfrac{3}{5}+\dfrac{2}{5}\)
\(\dfrac{4}{5}.x=1\)
\(x=1:\dfrac{4}{5}\)
\(x=\dfrac{5}{4}\)
\(\dfrac{-2}{5}+\dfrac{4}{5}.x=\dfrac{3}{5}\)
\(\dfrac{4}{5}.x=\dfrac{3}{5}+\dfrac{2}{5}\)
\(\dfrac{4}{5}.x=1\)
\(x=\) \(1:\dfrac{4}{5}\)
\(x=1.\dfrac{5}{4}\)
\(x=\dfrac{5}{4}\)