\(\dfrac{1}{4}xy\cdot\left(x^3-2x-6\right)\\ =\dfrac{1}{4}x^4y-\dfrac{1}{2}x^2y-\dfrac{3}{2}xy\)
Đúng 2
Bình luận (1)
\(\dfrac{1}{4}xy\cdot\left(x^3-2x-6\right)\\ =\dfrac{1}{4}x^4y-\dfrac{1}{2}x^2y-\dfrac{3}{2}xy\)