\(x^2+\left(y-\dfrac{1}{10}\right)^{2018}=0\\ \Leftrightarrow x^2+\left[\left(y-\dfrac{1}{10}\right)^{1009}\right]^2=0\\ \Leftrightarrow\left[{}\begin{matrix}x^2=0\\\left(y-\dfrac{1}{10}\right)^{1009}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\y=\dfrac{1}{10}\end{matrix}\right.\)
Tìm x:
a/\(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)
b/\(\dfrac{x^2}{-6}=-\dfrac{24}{25}\)
c/\(\dfrac{x+4}{20}=\dfrac{5}{x+4}\)
d/\(2,5:4x=0,5:0,2\)
e/\(\dfrac{1}{5}x:3=\dfrac{2}{3}:0,25\)
g/\(1,25:0,8=\dfrac{3}{8}:0,2x\)
f/\(-3:\left(-2\dfrac{1}{4}\right)=\dfrac{3}{4}:\left(-6x\right)\)
h/\(3:\dfrac{2}{5}x=1:0,01\)
j/\(2:1\dfrac{1}{4}=\dfrac{1}{2}:2x\)
l/\(\dfrac{4}{x-1}=\dfrac{x-1}{9}\)
1.viết tất cả các tỉ lệ thức từ các đẳng thức sau
a) 3*5=-1*-15
b) 4*9=-3*-12
c)3*b=7*c
d) a*x=b*y
2.tìm x
a) \(\dfrac{x-1}{4}=\dfrac{9}{x-1}\)
b)\(\dfrac{x+2}{5}=\dfrac{20}{x+2}\)
1,Chứng minh rằng:
\(\dfrac{1}{2^2}+\dfrac{1}{3^2}+...+\dfrac{1}{1990^2}< \dfrac{3}{4}\)
2,Chứng minh rằng:
\(1< \dfrac{x}{x+y}+\dfrac{y}{y+z}+\dfrac{z}{z+x}< 2\)
\(\dfrac{x}{y+z+1}=\dfrac{y}{x+z+2}=\dfrac{z}{x+y-3}=x+y+z\)
\(\dfrac{x^3}{8}=\dfrac{y^3}{64}=\dfrac{z^3}{216}\) và \(x^2+y^2+z^2=14\)
1. tim x biet
\(\left|x-3\right|-\left|x+1,5\right|=0\)
x\(^2\)+(y-\(\dfrac{1}{10}\))\(^4\)=0
\(\left|x+1\right|+\left|x+2\right|=0\)
Tìm a,b,c biết:
\(\dfrac{1}{2}a=\dfrac{2}{3}b\) = \(\dfrac{3}{4}c\)