Ta có :
\(\dfrac{2x+3}{5x+2}=\dfrac{4x+5}{10x+2}\)
\(\Leftrightarrow\left(2x+3\right)\left(10x+2\right)=\left(4x+5\right)\left(5x+2\right)\)
\(\Leftrightarrow2x\left(10x+2\right)+3\left(10x+2\right)=4x\left(5x+2\right)+5\left(5x+2\right)\)
\(\Leftrightarrow20x^2+4x+30x+6=20x^2+8x+25x+10\)
\(\Leftrightarrow20x^2+34x+6=20x^2+33x+10\)
\(\Leftrightarrow20x^2+34x+6-20x^2-33x-10=0\)
\(\Leftrightarrow x-4=0\)
\(\Leftrightarrow x=4\)
Vậy x = 4
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