\(f\left(x\right)=2x^2-7x+3\)
\(f\left(x\right)=2x^2-x-6x+3\)
\(f\left(x\right)=x\left(2x-1\right)-3\left(2x-1\right)\)
\(f\left(x\right)=\left(x-3\right)\left(2x-1\right)\)
\(f\left(x\right)=0\Leftrightarrow\left(x-3\right)\left(2x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{1}{2}\end{matrix}\right.\)
Đúng 0
Bình luận (1)