Violympic toán 6

HH

1. thực hiện phép tính

a. \(\dfrac{11}{21}\)+\(\dfrac{-4}{7}\)

b. \(\dfrac{5}{15}\)+\(\dfrac{14}{25}\)-\(\dfrac{12}{9}\)+\(\dfrac{2}{7}\)+\(\dfrac{11}{25}\)

c. \(\dfrac{2}{3}\)+\(\dfrac{5}{7}\)-\(\dfrac{3}{14}\)

d. \(\dfrac{2}{5}\)-\(\dfrac{3}{7}\)+\(\dfrac{9}{45}\)

e.\(\dfrac{21}{47}\)+\(\dfrac{9}{45}\)+\(\dfrac{26}{47}\)+\(\dfrac{45}{5}\)

f. \(\dfrac{15}{12}\)-\(\dfrac{18}{13}\)+\(\dfrac{5}{13}\)-\(\dfrac{3}{12}\)

g. \(\dfrac{-8}{18}\)-\(\dfrac{15}{27}\)

h.\(\dfrac{3}{7}\)+\(\dfrac{-5}{2}\)-\(\dfrac{3}{5}\)

i.(\(\dfrac{11}{12}\):\(\dfrac{33}{16}\)).\(\dfrac{3}{5}\)

H24
24 tháng 3 2018 lúc 17:48

a) \(\dfrac{11}{21}+\dfrac{-4}{7}=\dfrac{11}{21}+\dfrac{-12}{21}=\dfrac{-1}{21}\)

b) \(\dfrac{5}{15}+\dfrac{14}{25}-\dfrac{12}{9}+\dfrac{2}{7}+\dfrac{11}{25}=\dfrac{1}{3}+\dfrac{14}{25}-\dfrac{4}{3}+\dfrac{2}{7}+\dfrac{11}{25}\)

\(=\left(\dfrac{1}{3}-\dfrac{4}{3}\right)+\left(\dfrac{14}{25}+\dfrac{11}{25}\right)+\dfrac{2}{7}=-1+1+\dfrac{2}{7}=\dfrac{2}{7}\)

c) \(\dfrac{2}{3}+\dfrac{5}{7}-\dfrac{3}{14}=\dfrac{28}{42}+\dfrac{30}{42}-\dfrac{9}{42}=\dfrac{49}{42}=\dfrac{7}{6}\)

d) \(\dfrac{2}{5}-\dfrac{3}{7}+\dfrac{9}{45}=\dfrac{2}{5}-\dfrac{3}{7}+\dfrac{1}{5}=\dfrac{14}{35}-\dfrac{15}{35}+\dfrac{7}{35}=\dfrac{6}{35}\)

e) \(\dfrac{21}{47}+\dfrac{9}{45}+\dfrac{26}{47}+\dfrac{45}{5}=\dfrac{21}{47}+\dfrac{1}{5}+\dfrac{26}{47}+\dfrac{45}{5}=\left(\dfrac{21}{47}+\dfrac{26}{47}\right)+\left(\dfrac{1}{5}+\dfrac{45}{5}\right)\)

\(=1+\dfrac{46}{5}=\dfrac{51}{5}\)

f) \(\dfrac{15}{12}-\dfrac{18}{13}+\dfrac{5}{13}-\dfrac{3}{12}=\left(\dfrac{15}{12}-\dfrac{3}{12}\right)+\left(-\dfrac{18}{13}+\dfrac{5}{13}\right)=1+\left(-1\right)=0\)

g) \(\dfrac{-8}{18}-\dfrac{15}{27}=\dfrac{-4}{9}-\dfrac{5}{9}=\dfrac{-9}{9}=-1\)

h)\(\dfrac{3}{7}+\dfrac{-5}{2}-\dfrac{3}{5}=\dfrac{30}{70}+\dfrac{-175}{70}-\dfrac{42}{70}=\dfrac{-187}{70}\)

i) \(\left(\dfrac{11}{12}:\dfrac{33}{16}\right).\dfrac{3}{5}=\dfrac{11}{12}.\dfrac{16}{33}.\dfrac{3}{5}=\dfrac{11.16.3}{12.33.5}=\dfrac{4}{15}\)

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