\(\frac{x-1}{-15}=\frac{-60}{x-1}\)
\(\Leftrightarrow\left(x-1\right)^2=900\\ \Leftrightarrow\left(x-1\right)^2=\left(\pm30\right)^2\\ \Rightarrow x-1\in\left\{30;-30\right\}\)
\(\Rightarrow\left[{}\begin{matrix}x-1=30\\x-1=-30\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=31\\x=-29\end{matrix}\right.\)
Vậy...
1. tìm x
a.\(x+\dfrac{1}{2}=5^3:5^2\)
b. \(\dfrac{x-1}{-15}\)=\(\dfrac{-60}{x-1}\)
c. \(\dfrac{2x+1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+3y-1}{6x}\)
a,\(\dfrac{x}{-4}=\dfrac{-9}{x}\)
b,\(\dfrac{x-1}{-15}=\dfrac{-60}{x-1}\)
c,\(\dfrac{2x+1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+3y-1}{6x}\)
d,\(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\)
Ai tìm x giúp mình với!!Mình sẽ tích điểm cho!!
Tìm x , y ,z :
a, \(\dfrac{x+z+1}{x}=\dfrac{z+x+2}{y}=\dfrac{x+y-3}{z}=\dfrac{1}{x+y+z}\)
b, 10x = 6y và \(2x^2-y^2=-28\)
c, \(\dfrac{1+2y}{18}=\dfrac{1+4y}{24}=\dfrac{1+6y}{6x}\)
d, \(\dfrac{2x+1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+3y-1}{6x}\)
Tìm x ; y biết : \(\dfrac{2x+1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+3y-1}{6x}\)
a, tìm x,y \(\dfrac{2x+1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+3y-1}{6x}\)
b, Vẽ đồ thị hàm số y=\(-\dfrac{2}{3}\left|x\right|\)
Tìm x và y biết:
\(a,\dfrac{2x+1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+3y-1}{6x}\)
\(b,x\left(x-y\right)=\dfrac{3}{10}\)và \(y\left(x-y\right)=-\dfrac{3}{50}\)
Giá trị của x thoả mãn: \(\dfrac{2x+1}{5}\)=\(\dfrac{3y-2}{7}\)=\(\dfrac{2x+3y-1}{6x}\)
(với 2x+3y-1 khác 0) là x=....?
Bài 1: Tìm x,y:
\(\dfrac{2x+1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+3y+1}{6x}\)
Bài 5: cho \(\dfrac{a}{b}=\dfrac{c}{b}=\dfrac{c}{d}\) và a+b+c\(\ne\)0
Tính M=\(\dfrac{a^3.b^2.c^{1930}}{b^{1935}}\)
Câu hỏi:
a) -4x(x-5)-2x(8-2x)=3
b) \(\dfrac{2x-1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+3y-1}{6x}\)
Giúp mik nhé! Cảm ơn bn nhiều!
