Giải:
\(A=\left(a+b\right)-\left(a-b\right)+\left(a-c\right)-\left(a+c\right)\)
\(\Leftrightarrow A=a+b-a+b+a-c-a-c\)
\(\Leftrightarrow A=\left(a-a+a-a\right)+\left(b+b\right)+\left(-c-c\right)\)
\(\Leftrightarrow A=2b-2c\)
\(\Leftrightarrow A=2\left(b-c\right)\)
Vậy ...
a)
A = ( a+b) - (a-b) + (a-c) - (a+c)
A = a + b - a + b + a- c - a - c
A = ( a - a + a -a) + ( b + b) + ( -c - c )
= 2b -2c