Question

1) A= \(\dfrac{5.2^3+40.7}{40.2^3}\)

Answer 1

Ta có: \(A=\dfrac{5.2^3+40.7}{40.2^3}\)

\(=\dfrac{5.2^3+5.2^3.7}{40.2^3}\)

\(=\dfrac{5.2^3\left(1+7\right)}{5.2^3.8}\)

\(=1\)

Vậy \(A=1.\)

Answer 2

\(A=\dfrac{5.2^3+40.7}{40.2^3}=\dfrac{40+40.7}{40.2^3}\)

\(=\dfrac{40\left(1+7\right)}{40.8}=\dfrac{8}{8}=1\)

Answer 3

A= \(\dfrac{5.2^3+40.7}{40.2^3}\)

=\(\dfrac{40+40.7}{40.2^3}\)

=\(\dfrac{40\left(1+7\right)}{40.8}\)

=\(\dfrac{8}{8}=1\)