Question

|1-2x|+x+2=0

Answer 1

\(\left|1-2x\right|\)+x=-2

=> 1-2x+x=-2;2

TH1 1-2x+x=-2

1-3x=-2

3x=1-(-2)

3x=1

x=1:3=\(\dfrac{1}{3}\)

TH2 1-2x+x=2

1-3x=2

3x=1-2

3x=-1

x=-1:3=\(\dfrac{-1}{3}\)

Answer 2

\(\left|1-2x\right|+x+2=0\)

Với \(x\ge\dfrac{1}{2}\) ta có:

\(1-2x+x+2=0\)

\(\Leftrightarrow3-x=0\)

\(\Leftrightarrow x=3\left(TM\right)\)

Thay vào ko TM(loại)

Với \(x< \dfrac{1}{2}\) ta có:

\(-1+2x+x+2=0\)

\(\Leftrightarrow1+3x=0\Rightarrow x=-\dfrac{1}{3}\left(TM\right)\)

Vậy...