Question

Answer 1

a: \(=\sqrt{2}\left(2\sqrt{3}-2\sqrt{2}\right)-\sqrt{6}+2\)

\(=2\sqrt{6}-4-\sqrt{6}+2=\sqrt{6}-2\)

b: \(=\sqrt{16}-\sqrt{\dfrac{1}{36}}=4-\dfrac{1}{6}=\dfrac{23}{6}\)

c: \(=\sqrt{\dfrac{10}{3}:\dfrac{1}{5\left(2a-3\right)^2}}\)

\(=\sqrt{\dfrac{50\left(2a-3\right)^2}{3}}\)

\(=\left(3-2a\right)\cdot\dfrac{5\sqrt{6}}{3}\)

d: \(=\sqrt{a}+2-\sqrt{a}-2=0\)

e: \(=\dfrac{2\sqrt{3}}{3}+\sqrt{3}-6\sqrt{3}+2-\sqrt{3}=2-\dfrac{16}{3}\sqrt{3}\)

f: \(=\dfrac{\sqrt{a}+2+\sqrt{a}-2}{a-4}\cdot\dfrac{a-4}{1}=2\sqrt{a}\)

g: \(=\left(1-\sqrt{7}\right)\left(\sqrt{7}+1\right)=1-7=-6\)

i: \(=\sqrt{5}-1+2-\sqrt{5}=1\)

k: =x-2022+3-x=-2019