a) \(\dfrac{2}{3}+20\%\cdot\dfrac{10}{7}=\dfrac{2}{3}+\dfrac{1}{5}\cdot\dfrac{10}{7}=\dfrac{2}{3}+\dfrac{2}{7}=\dfrac{20}{21}\)
b) \(\dfrac{3}{4}+1\dfrac{4}{5}:\dfrac{3}{2}-1=\dfrac{3}{4}+\dfrac{9}{5}:\dfrac{3}{2}-1=\dfrac{3}{4}+\dfrac{6}{5}-1=\dfrac{39}{20}-1=\dfrac{19}{20}\)
c,d tự làm
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