Question

Answer 1

Ta có \(-3x^2+2x+1=-3x^2-2+x\Leftrightarrow2x+1=-2+x\Leftrightarrow x=-3\)

Vậy với x = -3 thì f(x) = g(x) 

Answer 2

\(f\left(x\right)=g\left(x\right)\Leftrightarrow-3x^2+2x+1=-3x^2-2+x\)

\(\Leftrightarrow2x-x=-2-1\Leftrightarrow x=-3\)

Answer 3

\(f\left(x\right)=g\left(x\right)\\ \Rightarrow-3x^2+2x+1=-3x^2-2+x\\ \Rightarrow-3x^2+2x+1+3x^2+2-x=0\\ \Rightarrow x+3=0\\ \Rightarrow x=-3\)