Question

Answer 1

Lời giải:
ĐKXĐ: $x\geq -2$

PT $\Leftrightarrow (x+3-2\sqrt{x+2})+2\sqrt{x+2}=3x-6\sqrt{x+2}+11$

$\Leftrightarrow x+3=3x-6\sqrt{x+2}+11$

$\Leftrightarrow 2x+8=6\sqrt{x+2}$

$\Leftrightarrow x+4=3\sqrt{x+2}$

$\Leftrightarrow (x+2)-3\sqrt{x+2}+2=0$

$\Leftrightarrow (\sqrt{x+2}-1)(\sqrt{x+2}-2)=0$

$\Rightarrow \sqrt{x+2}-1=0$ hoặc $\sqrt{x+2}-2=0$

$\Leftrightarrow x=-1$ hoặc $x=2$ (đều tm)